A small block of mass `m` is projected on a larger block of mass `10 m` and length `l` with a velocity `v` as shown in the figure. The coefficient of friction between the two block is `mu_(2)` while that between the lower block and the ground is `mu_(1)`. Given that `mu_(2) gt 11 mu_(1)`.

(a) Find the minimum value of `v`, such that the mass `m` falls off the block of mass `10 m` .
(b) If `v` has minimum value, find the time taken by block `m` to do so.

Explanation

`V_("min")= sqrt(2a_(s)I)=sqrt((22)/(10)(mu_(2)-mu_(1))gl,)(b)t=(v_(min"))/(a_(r))=sqrt((2ol)/(11(mu_(2)-mu_(1)g)))`