Three deminsions. Three point particles are fixed in place in a xyz coordinate system. Particle A, at the origin, has mass `m_A`. Particle B, at xyz coordinates (2.00d,1.00d. 200), has mass 2.00`m_A`, and particle C, at coordinates (-1.00d,2.00d,-3.00d), has mass `3.00m_A`. A fourth particle D,with mass `4.00 m_A`,is to be placed near the other particles. In terms of distance d, at what (a)x, (b)y, and (c)z coordinate should D be placed so that the net gravitational force on A from B, C, and D is zero ?

Explanation

`(a) -1.88d, (b) -3.90d, (c ) 0.489d`. In this way, we are able to deduce that (x,y,z) = (1.88d,3.90d, 0.489d).