At what angular speed of rotation is the surface material on the equator of a neutron star on the verge of flying off the star if the star is spherical with a radius of 18.0 km and a mass of `7.72 xx 10^24` kg?

Explanation

To find the angular speed of rotation at which the surface material on the equator of a neutron star is on the verge of flying off, we can use the concept of centripetal force and gravitational force. Here’s a step-by-step solution:

### Step 1: Understand the Forces Involved
The centripetal force required to keep the surface material in circular motion at the equator is provided by the gravitational force. Therefore, we can set up the equation:

\[ F_{\text{centripetal}} = F_{\text{gravity}} \]
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