" R5."6cosec x+9sec x

Let f(x)=2 cosec 2x + sec x+cosec x , then the minimum value of f(x) for x in (0,pi/2) is

Let f(x)=2 cosec 2x + sec x+cosec x , then the minimum value of f(x) for x in (0,pi/2) is

int_(0)^((pi)/(2)) ("4 sec x + 5 cosec x")/("sec x + cosec x") dx

(d)/(dx)(log tan((pi)/(4)+(x)/(2)))= (a) cosec x (b) -cosec x (c) sec x (d) -sec x

int (dx)/(tan x+ cot x+ sec x+ cosec x)

If y = sec^(-1) [ "cosec x"] + "cosec"^(-1) [sec x] + sin^(-1) [cos x] + cos^(-1)[sinx ], "then "(dy)/(dx) is equal to

If y=2 sin^(-1) (cos x)+5"cosec "^(-1) "(sec x). Find"(dy)/(dx) .

int_(0)^(pi//2) (3 Sec x + 5 cosec x)/(Sec x + cosec x) dx=

If Cot x = (5)/(12) then sec x + cosec x = ?

int (sec x cosec x)/(2 cot x- sec x cosec x)dx=