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log10 15(1+log15 30)+1/2log10 16(1+log4 ...

`log_10 15(1+log_15 30)+1/2log_10 16(1+log_4 7)-log_10 6(log_6 3+log_6 7)`

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Prove that (ii) log_(10)15(1+log_(15)30)+1/2 log_(10)16(1+log_(4)7)-log_(10)6(log_(6)3+1+log_(6)7) = 2

log_(10)15(1+log_(15)30)+(1)/(2)log_(10)16(1+log_(4)7)-log_(10)6(log_(6)3+log_(6)7)

log_10(log_2 3) + log_10(log_3 4) + log_10(log_4 5) + ........ + log_10 (log_1023 1024) simplifies to

Given that log_10 2=.3010 , log_10 3=.4771 , log_10 4=.6021 , log_10 5-.6990 , log_10 10=.7782 ,then prove that log_6 30=1.898

Given that log_10 2=.3010 , log_10 3=.4771 , log_10 4=.6021 , log_10 5-.6990 , log_10 10=.7782 ,then prove that log_6 45=2.1244

Given that log_10 2=.3010 , log_10 3=.4771 , log_10 4=.6021 , log_10 5-.6990 , log_10 10=.7782 ,then prove that log_6 5=.8982

Given that log_10 2=.3010 , log_10 3=.4771 , log_10 4=.6021 , log_10 5-.6990 , log_10 10=.7782 ,then prove that log_2 6=2.5854

Given that log_10 2=.3010 , log_10 3=.4771 , log_10 4=.6021 , log_10 5-.6990 , log_10 10=.7782 ,then prove that log_4 9=1.5848

Given that log_10 2=.3010 , log_10 3=.4771 , log_10 4=.6021 , log_10 5-.6990 , log_10 10=.7782 ,then prove that log_9 24=1.4465