In YDSE, D = 1.2m and d= 0.25cm, the slits are illuminated with coherent 600nm light. Calculate the distance y above the central maximum for which the average intensity on the screen is 75% of the maximum.

In a Young's double slit experiment,two slits are 1.5 mm apart and a screen in placed at a distance 1.2 m from the plane of the slits .The slits are illuminated with light of wavelength 6,000 overset @A .Find the inimum distance from the central maximum for which the intensity is half of the maximum intensity.

In an arrangement of double slit arrangement fig. The slits are illuminated by light of wavelenth 600 mm. The distance of the first point on the screen from the centre maximum where intensity is 75% of central maximum is

In a Young's double slit experiment , the slits are Kept 2mm apart and the screen is positioned 140 cm away from the plane of the slits. The slits are illuminatedd with light of wavelength 600 nm. Find the distance of the third brite fringe. From the central maximum . in the interface pattern obtained on the screen frings from the central maximum. 3

In a Young's double slit experiment , the slits are Kept 2mm apart and the screen is positioned 140 cm away from the plane of the slits. The slits are illuminatedd with light of wavelength 600 nm. Find the distance of the third brite fringe. From the central maximum . in the interface pattern obtained on the screen frings from the central maximum. 3

In a Young's double slit experiment lamda= 500nm, d=1.0 mm andD=1.0m . Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

In a Young's double slit experiment lamda= 500nm, d=1.0 mm andD=1.0m . Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

In a Young's double slit experiment lamda= 500nm, d=1.0 mm andD=1.0m . Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.