`C_4H_11N` on reaction with `HNO_2` forms tertiary alcohol . Thus , `C_4H_11N` is

C_4 H_(11) N on reaction with HNO_2 forms tertiary alcohol. Thus, C_4 H_(11) N is

An optically inactive compound (A) having molecular formula C_4H_11N on treatment with HNO_2 gave an alcohol (B). (B) on heating at 440 K gave an alkene (C). (C) on treatment with HBr gave an optically active compound (D)having the molecular formula C_4H_9Br . Identify A, B, C and D and write down their structural formulae. Also write equations involved.

C_(4)H_(11)N can represent :

C_(4)H_(11)N can represent :

HCI is added to a hydrocarbon 'A' (C_4H_8) to give a compound 'B'which on hydrolysis with aqueous alkali forms tertiary alcohol 'C' (C_4H_10O) .Identify 'A','B' and'C'.

An organic compounds 'X' with the molecular formula C_4H_11 N reacts with C_6H_5 SO_2Cl and forms the compound 'Y' .If 'Y' is soluble in alkali ,''X' may be