10 men and 6 women are to seated in a row so that no two wowen sit together the number of ways they can ne seated is

10 men and 6 women are to be seated in a row so that all women sit together. The number of ways they can be seated, is

m men and w women are to be seated in a row so that no two women sit together.If m>w then the number of ways in which they can be seated is

5 men and 6 women have to be seated in a straight row so that no two women are together. Find the number of ways this can be done.

If n men and m women are to be seated in a row so that no two women sit together . If ngtm , then show that number of ways in which they can be seated is (n!(n+1)!)/((n-m+1)!)

m men and n women are to be seated in a row so that no two women sit together. If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!) .

m men and n women are to be seated in a row so that no two women sit together.If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!)