Block A of mass m is placed over a wedge of same mass m. Both the block and wedge are placed on a fixed inclined plane. Assuming all surfaces to be smooth calculate the displacement of the block A in ground frame in `1s`.

Block A of mass m is placed over a wedge of same mass m. Both the block and wedge are placed on a fixed inclined plane. Assuming all surfaces to be smooth, the displacement of the block A in ground frame in 1s is (gsin^(2)theta)/(x+sin^(2)theta) then the value of x is:

A block of mass 'm' is placed on wedge of mass 'M'. If all the surfaces are smooth Accelaration of wedge 'A' is

A block of mass m is placed on a smooth wedge of mass M, as shown in the figure . Just after placiing block m over wedge M.

A block of mass m is placed at rest on a smooth wedge of mass M placed at rest on a smooth horizontal surface. As the system is released

A block of mass m is placed at rest on a smooth wedge of mass M placed at rest on a smooth horizontal surface. As the system is released

A block of mass m is at rest over the rough surface of the fixed wedge.

A horizontal force F acts on a wedge of mass m_1 as shown. A block of mass is placed on the front wall of my. Assuming all contact surfaces to be smooth and m_2 moves on a smooth horizontal surface.

A block of mass 'm' is placed on wedge of mass 'M'. If all the surfaces are smooth Normal reaction between the wedge and block is

A block of mass m is initially lying on a wedge of mass M with an angle of inclination theta as shown in figure. Calculate the displacement of the wedge when the block is released and reaches to the bottom of the wedge.

a Block of mass m is placed on a wedge of mass M there is no friction between the block and the wedge .The minmum coefficient of friction between the wedge and the gound so that wedge does not move is,