[" A body moves according to the formula "v=1+t^(2)],[" where "v" is the velocity at time "t." The acceleration after "3],[" sec will be "(v" in "cm/sec)]

A body moves according to the formula v=l+t^2 , where V is the velocity at time t. The acceleration after 3sec will be ( v in cm//sec )

A body moves according to the formula v=l+t^2 , where V is the velocity at time t. The acceleration after 3sec will be ( v in cm//sec ) a) 24cm//sec^2 b) 12cm//sec^2 c) 6cm//sec^2 d)None of these

Displacement x at time t is x=t-t^(3) . If v is the velocity and a the acceleration at time t, then :v =

The law of motion of a particle is S = t^(n) , where n ge 3 .If v is the velocity and a the acceleration at time t, then (aS)/(v^(2))=

A particle moves on a line according to the law s=at^(2)+bt+c . If the displacement after 1 sec is 16 cm, the velocity after 2 sec is 24 cm/sec and acceleration is 8cm//sec^(2) , then

A particle moves on a line according to the law s=at^(2)+bt+c . If the displacement after 1 sec is 16 cm, the velocity after 2 sec is 24 cm/sec and acceleration is 8cm//sec^(2) , then

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

A particle moves with an initial velocity v_(0) and retardation alpha v , where v is the velocity at any time t.

If a particle moves in a circle of radius 4m at speed given by v = 2t where v is in m/s and t in sec at t = 4sec, acceleration of particle will be