(dy)/(dx)=(1)/(x+y+1)

Then number of solution of (dy)/(dx)=(y+1)/(x-1),y(1)=2 is

The number of solution of (dy)/(dx)=(y+1)/(x-1) when y(1)=2 is

If the homogeneous form of the differential equation (dy)/(dx)=(x + y + 1)/( x - y +1) is (dY)/(dX) = (X + Y)/(X - Y) then what is the relation between Y and y?

The Solution of (dy)/(dx)=(1-y)/(1-x) is

The solution of (dy)/(dx)=(1-y)/(1-x) is

" The solution of "(dy)/(dx)=(1-y)/(1-x)

The solution of (dy)/(dx) = (x + y +1)/(x + y -1) is

(dy)/(dx)=(x+y+1)/(x+y-1) , given y=1, when x=1

(dy)/(dx)=(x+y+1)/(x+y-1) given y=1 when x=1