Let `f:R to R, g: R to R` be two functions given by `f(x)=2x-3,g(x)=x^(3)+5`. Then `(fog)^(-1)` is equal to

Let f: R rarr R, g: R rarr R be two functions given by f(x)=2x-3, g(x)=x^(3)+5 . Then , (fog)^(-1) is equal to

Let f : R rarr R , g : R rarr R be two functions given by f(x) = 2x - 3, g(x) = x^(3) + 5 . Then (fog) (x) is equal to

Let f : R rarr R , g : R rarr R be two functions given by f(x) = 2x - 3, g(x) = x^(3) + 5 . Then (fog) (x) is equal to

Let f:R rarr R , g : R rarr R be two function given by f(x) =5x-4 and g(x) = x^(3)+7 then (fog)^(-1) (x) equals

Let f:R→R, g:R→R be two functions given by f(x)=2x+4 , g(x)=x-4 then fog(x) is

Let f:R toR and g:R to R be two functions given by f(x)=cosx and g(x)=3x^(2) . Show that gof!=fog .