Pulley system

The moment of inertia of the pulleys system as shown in the figure-5.103 is 4 kgm^(2) The radii of bigger and smaller pulleys 2 mand 1m respectively.The angular acceleration of the pulley system is: (take = 10 m//s^(2) )

In the pulley system shown the two upper pulleys are fastened together to form single unit. The cable is wrapped around the smaller pulley with its end secured to the pulleys so that it cannot slip. Determine the upward acceleration of block B if A has downward acceleration of 2 m//s^(2) :

A step pulley system is shown in figure-2.50. Find the relation in masses m and M for which the system remain in equilibrium. Assume string will not slide over the pulleys. ((r_(1))/(r_(2))=(1)/(2),(r_(3))/(r_(4))=(3)/(4)) [(M)/(m)=(3)/(8)sintheta]

A pulley system has a velocity ratio 5. Draw a neat labelled diagram of the pulley system to lift a load by applying the effort in a convenient direction. Mark the tension in your diagram. If a load of 10 kgf is pulled up by a distance of 2 m in 10 s, calculate the power developed by the effort (given g = 10 m s^(-2) ).

Pulley mas system || Toppling

In the pulley-block system shown in figure, strings are light. Pulleys are massless and smooth. System is released from rest. In 0.3 seconds. .

A rigid massless beam is balanced by a particle of mass 4m in left hand side and a pulley particle system in right hand side. The value of x/y is

Find out the velocity of block B in a pulley block system as shown in figure.