श्रेणी `(1)/(3),(1)/(9),(1)/(27)` के अगले दो पद होंगे -

1/3,1/9,1/(27),….a_7

Find the sum to infinity of the following G.P. (i) 1, (1)/(3) , (1)/(9) . (1)/(27),… (ii) 2 , (-2)/(3) , (2)/(9) , (-2)/(27),… .

1-(3)/(1!)+(9)/(2!)-(27)/(3!)+....=

Find the value of 9^((1)/(3)),9^((1)/(9)).9^((1)/(27))...up to oo

Prove that 9^((1)/(3)) xx 9^((1)/(9)) xx 9^((1)/(27))……oo = 3

int((27)^(1+x)+9^(1-x))/(3^(x))

If x=9^(1/3) 9^(1/9) 9^(1/27) ...-> ∞ , y= 4^(1/3) 4^(-1/9) 4^(1/27) ....-> ∞ and z= sum_(r=1)^oo (1+i)^-r then , the argument of the complex number w = x+yz is