A block of mass 2 kg rests on the floor of an elevator , which is moving down with an acceleration 'g' , then the apparent weight of the block is [ take g = `10 m//s^(2)` ]

A man of mass 75 kg is standing in an elevator which is moving with an acceleration of 5 m//s^2 in upward direction.The apparent weight of the man will be (g=10 m//s^2)

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6m//s^(2) in upward direction. The apparent weight of the man will be (g=10m//s^(2))

What is the weight of a block of mass 10.5 kg ? Take g= 10 m s^(-2)

.A block is kept on the floor of an elevator at rest.The elevator starts descending with an acceleration of 12m/s^(2) .Find the displacement of the block during the first 0*2safter the start.Take g=10m/s^(2)

a block is kept on the floor of an elevator at rest. The elevator starts descending with an acceleration of 12 m/s^2 . Find the displacement of the block during the first 0.2 s after the start. Take g=10 m/s^2 .