Cartain mass of starach, `(C_(6)H_(10)O_(5))_(n)`, is burnt completely . If 26.4 kg `CO_(2)` is produced, the mass of water produced simultaneously is-

Certain mass of starch, (C_(6)H_(10)O_(5))_(n) , is burnt completely . If 26.4 kg CO_(2) is produced, the mass of water produced simultaneously is-

6.0 gm of gaseous hydrogen produce 17.6 gm CO_(2) on complete combustion. The mass of water formed simultaneously is:

When C_(2)H_(4) is burnt in air, carbon dioxide and water are formed. If on combustion of C_(2)H_(4),2 moles of CO_(2) is produced, calculate the number of drops of water produced, calculate the number of drops of water produced along with this quantity of CO_(2) if each drop contains 6.022 xx 10^(21) water molecules.

N_(2)O_(4) reacts with water to produce

Calculating osmotic pressure: The fomula for low molecular mass starch is (C_(6)H_(10)O_(5))_(n) , where n averages 2.00xx10^(2) . When 0.798g of starch is dissolved in 100.0 mL of water solution, what is the osmotic pressure at 25^(@)C ? Strategy: Work out the molecular mass of (C_(6)H_(10)O_(5))_(200) , and use it to obtain the molarity of the starch solution. Substitute into the formula for the osmotic pressure, pi=CRT .

when 22.4 L of C_(4) H_(8) at STP is burnt completely , 89.6 L of CO_(2) gas at STP and 72 g water are Produced . The volume of the oxygen gas at STP consumed in the reaction is closest to

A mixture of hydrocarbon C_(2)H_(2).C_(2)H_(4) & CH_(4) in mole ration of 2:1:2 is burnt completely in the pressence of air containing 80%N_(2) % 20% O_(2) by volume. The mass of air required for the complete combustion of the one gm of mixture is

1 ml of gaseous aliphatic compound C_(n) H_(3n) O_(m) is completely burnt in an excess of O_(2) . The contraction in volume is

1 ml of gaseous aliphatic compound C_(n) H_(3n) O_(m) is completely burnt in an excess of O_(2) . The contraction in volume is