`9-3-:1/3+1=`

The sum to infinity of the progression 9-3 + 1-1/3 + ……..is

(4)/(9^(1/3)-3^(1/3)+1) is equal to 3^(1/3)+1b3^(1/3)-1c*3^(1/3)+2d*3^(1/3)-2

Find the value of (( x -y )^3 + ( y - z )^3 + ( z - x )^3 )/ (9 ( x - y )( y - z ) ( z - x )) 1 . 0 2 . 1/9 3 . 1/3 4. 1

The sum of infinity of the progression 9-3+1-(1)/(3)+… is

9xx(-1/3)xx(-3)xx(-1/9)= 1 (b) -1 -3 (d) 3

The simplified of ((1)/(3)-:(1)/(3) xx(1)/(3))/((1)/(3)-:(1)/(3)"of"(1)/3)-(1)/(9) is

The following steps are involved in finding the value of 10 (1)/(3) xx 9(2)/(3) by using an appropriate indentity . Arrange them in sequential order . (A) (10)^(2) - ((1)/(3))^(2) = 100 - (1)/(9) (B) 10(1)/(3) xx 9(2)/(3) = (10 + (1)/(3)) (10 - (1)/(3)) (C) (10 + (1)/(3)) (10 - (1)/(3)) = (10)^(2) - ((1)/(3))^(2) [because (a + b) (a -b) = (a^(2) - b^(2))] (D) 100 - (1)/(9) = 99 + 1 - (1)/(9) = 99(8)/(9)

9 3/4-:[2 1/6 +{ 4 1/3-(1 1/2+1 3/4)}]

(4)/(9^((1)/(3))-3^((1)/(3))+1) is equivalent to :

(9)^(1/3)xx(3)^(1/3) IS EQUAL TO