`(dy)/(dx)=(x^2-y^2)/(x y)`

The general solution of (dy)/(dx)=(2x-y)/(x+2y) is

Solve (dy)/(dx)=(x-2y+5)/(2x+y-1)

(dy)/(dx)=(x-y+3)/(2x-2y+5)

Solve the differential equation: (dy)/(dx)=(x+y+2)/(2(x+y)-1)

Solve (dy)/(dx)=(2x-y+1)/(x+2y-3)

Let y=f (x) and x/y (dy)/(dx) =(3x ^(2)-y)/(2y-x^(2)),f(1)=1 then the possible value of 1/3 f(3) equals :

x(dy)/(dx)+(y^(2))/(x)=y

Solution of the differential equation (dy)/(dx)+(x-2y)/(2x-y)=0 is