Slope of any tangent to a curve is given by `3x^(2)-4x` for all values of `x` and curve passes through the point `(1,0)` then local maximum value of `f(x)`

The slope of a curve at any point (x, y) on it is (4x-3) . If the curve passes through the point (1, 3), then its equation is

The slope of tangent at a point P(x, y) on a curve is - x/y . If the curve passes through the point (3, -4) , find the equation of the curve.

Slope of a curve at any point (x, y) on it is (4x-3) . If u passes through the point (1, 3), then its equation is

If f'(x)=x-1, the equation of a curve y=f(x) passing through the point (1,0) is given by

The slope at any point of a curve y=f(x) is given by (dy)/(dx)= 2x and it passes through (1,-1) . The equation of the curve is

The slope of the tangent to a curve at any point (x,y) on its given by (y)/(x)-(cot y)/(x)(cos y)/(x),(x>0,y>0) and the curve passes though the point (1,pi/4)* Find the equation of the curve.

The slope of the tangent to a curve y=f(x) at (x,f(x)) is 2x+1. If the curve passes through the point (1,2) then the area of the region bounded by the curve,the x -axis and the line x=1 is (A) (5)/(6)(B)(6)/(5)(C)(1)/(6)(D)1

If the slope of tangent at point (x,y) of curve y=f(x) is given by (2y)/(x^(2)) .If this curve passes through the centre of the circle x^(2)+y^(2)-2x-2y=0. Then the curve is :

The slope at any point of a curve y = f(x) is given (dy)/(dx) = 3x^(2) and it passes through (-1,1) . The equation the curve is