An electron of mass `9xx10^(-31)` kg revolves in a circle of radius 0.53 Å around the nucleus of hydrogen atom with a velocity of `2.2xx10^(6) "ms"^(-1)`. What is the angular momentum of the electron ?

An electron of mass 9 xx 10^(-31) kg revolves in a circle of radius 0.53 Å around the nucleus of hydrogen with a velocity of 2.2 xx 10^(6) "ms"^(-1) . Show that its angular momentum is equal to h//2pi , where h is Plank's constant of value 6.6 xx 10^(-34) Js .

An electron of mass 9xx10^(-31) kg revolues in a circle of radius 0.53 A around the nucles of hydrogen with a velocity of 2.2xx10^(6) ms^(-1) . Show that angular momentum of electron is h//2 pi , where h is plack's constant.

Mass of an electron is 9.0xx10^(-31) kg . It revolves around the nucleus of an atom in a circular orbit of radius 4.0 Å with a speed of 6.0 xx10^(6) ms^(-1) . Calculate the angular momentum of the electron.

An electron revolves around a nucleus of an atom in a circular orbit of radius 4A^0 with a speed of 5xx10^6 m//s . What is the angular momentum of the electron ?

An electron of mass 9 xx 10^(-31) kg revolves around a nucleus in a circular orbit of radius 0.53 Å . What is the angular momentum of the electron? (Velocity of electron is, v=2.2 xx 10^(6) ms^(-1)).

An electron revolves around the nucleus of an atom in a circular orbit of radius 4 Å with a speed of 5xx 10^(6)m//s . What is the angular momentum of the electron ? [ m_(e) = 9 xx 10^(-31) kg ].

In hydrogen atom, the electron is moving round the nucleus with velocity 2.18xx10^(6)ms^(-1) in an orbit of radius 0.528 A. The acceleration of the electron is .

In hydrogen atom, the electron is moving round the nucleus with velocity 2.18xx10^(6)ms^(-1) in an orbit of radius 0.528 A. The acceleration of the electron is .

The mass of an electron is 9.1xx10^(-31) kg and velocity is 2.99xx10^(10) cm s^(-1) . The wavelenth of the electron will be