If (6, –3) is the one extremity of diameter to the circle `x^(2) + y^(2) – 3x + 8y – 3 = 0` then its other extremity is

If (4,-2) is the one extremity of diameter to the circle x^(2)+y^(2)-4x+8y-4=0, then find its other extremity.

If (2,3) is an extremity of a diameter of the circle x^(2)+y^(2)-5x-8y+21=0 , then the other extremity of the diameter is

If (2,3) is an extremity of a diameter of the circle x^(2)+y^(2)-5x-8y+21=0 , then the other extremity of the diameter is

If one end of a diameter of the circle 3x^(2) + 3y^(2) - 9 x + 6y + 5 = 0 is (1 ,2) then the other end is _

The line x + 3y = 0 is a diameter of the circle x^(2) + y^(2) + 6x + 2y = 0 .

If one end of the diameter of the circle x^2 + y^2 - 8x - 4y + c = 0 is (-3, 2), then the other end is :

If (1,2)(2,a) are extremities of a diameter of the circle x^(2)+y^(2)-3x-4y+6=0 then a=

If (1,2) (2,a) are extremities of a diameter of the circle x^(2)+y^(2)_3x-4y+6=0 then a=

If (1,2) (2,a) are extremities of a diameter of the circle x^(2)+y^(2)_3x-4y+6=0 then a=

The line x+3y=0 is a diameter of the circle x^(2)+y^(2)-6x+2y=0