A particle at a distance of 1 m from the origin starts moving such that `dr//d theta = r`, where `(r, theta)` are polar coordinates. Then the angle between resultant velocity and tangential velocity component is

When a projectile is fired at an angle theta w.r.t horizontal with velocity u, then its vertical component:

A particle starts rotating from rest according to the formula theta = (t^(2)//64) - (t//8) " where " theta is the angle in radian and t in s . Find the angular velocity and angular acceleration at the end of 4 s .

A particle has two velocities of equal magnitude inclined to each other at angle theta . If one of them is halved, the angle between the other and the original resultant velocity is bisected by the new resultant. Then theta is (A) 120^0 (B) 45^0 (C) 60^0 (D) 90^0

A point object moves along an arc of a circle of radius 'R'. Its velocity depends upon the distance covered 'S' as V = Ksqrt(S) where 'K' is a constant. If ' theta' is the angle between the total acceleration and tangential acceleration, then