नाट्रोजन नाभिक `(._(7)^(14)N`) की बंधन ऊर्जा `MeV` में ज्ञात कीजिए `m_(N)=14.00307u`

Calculate the specific binding energy of the nucleus of ._(7)^(14)N . Given the rest mass of nucleus of ._(7)^(14)N=14.00307 u, the rest mass of proton =1.00783 u and the rest mass of neutron=1.00867 u.

._(6)C^(14) and ._(7)N^(14) are

._(7)^(14)N and ._(6)^(14)C are isobars

._(7)^(14)N and ._(6)^(14)C are isobars

Obtain the binding energy (in MeV. Of a nitrogen nucleus (._(7)^(14)N) , given m (._(7)^(14)N) = 14.00307 u .

Obtain the binding energy (in MeV) of a nitrogen nucleus (""_(7)^(14)N) , given m (""_(7)^(14)N) =14.00307 u.

Obtain the binding energy (in MeV) of a nitrogen nucleus (""_(7)^(14)N) , given m(""_(7)^(14)N) =14.00307" "u