Given for the following equilibrium taking place in 1 L flask at 300 K. `PC1_(5)(g)hArrPC1_(3)(g) + C1_(2)(g)` , `K_(c) = 4` Thus, degree of dissociations of `PC1_(5)` (g) is

For PCl_(5 (g)) hArr PCl_(3 (g)) + Cl_(2 (g)) at equilibrium , K_(P) = P//3 . Then degree of dissociation of PCl_(5) at that temperature is

Phosphorus pentachloride dissociates as follows, ina closed reaction vessel, PC1_(5(g))hArrPC1_(3(g)) + C1_(2(g)) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PC1_(5) is x, the partial pressure of PC1_(3) will be:

Phosphorus pentachloride dissociates as follows, ina closed reaction vessel, PC1_(5(g))hArrPC1_(3(g)) + C1_(2(g)) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PC1_(5) is x, the partial pressure of PC1_(3) will be:

In the following reaction PC1_(5)(g)hArrPC1_(3)(g) + C1_(2)(g) at constant temperature, rate of backward reaction is increase by:

Consider the following equilibrium reaction at T K in a 1L flask. (I) A(g)iffB(g)+C(g), K_(C_(1))=3 (II) B(g)iff D(g)+C(g), K_(C_(2))=? If initially 2 moles of A(g) are taken and allowed attain equilibrium, concentration of C(g) was formed to be 3M. What is the value of K_(C ) of second reaction ?

Consider the reaction (i) PC1_(5)(g)hArrPC1_(3)(g) + C1_(2)(g) N_(2)O_(4)(g)hArr2NO_(2)(g) The addition of an inert gas at constant volume

At a given temperature, the reaction, A(g)hArr 2N(g) , is in equilibrium in a closed flask. At the same temperature, the reaction c(g)hArr D(g)+E(g) is in equilibrium in an another closed flask. Values of equilibrium constants of these two reactions are K_(p1) and K_(p2) respectively and the total pressures of the equilibrium mixtures are P_1 and P_2 respectively. If K_(p1) : K_(p2) = 1 : 4 and P_1 : P_2 = 1 : 4 then the ratio of degree of dissociation of A(g) and C(g) are ( assume the degrees of dissociation of both are very small compared to 1)-

Assertion: Association of an inert gas at constant pressure to dissociation equilibrium of PC1_(5) hArr PC1_(3) + C1_(2) favours forward reaction. Reason: K_(c) =(alpha^(2))/(V(1 - alpha)) for the dissociation equilibrium of PC1_(5) where alpha is degree of dissociation of PC1_(5) .

The following equilibrium exists in a closed vessel in 1L capacity A(g)+3B(g)hArr4C(g) initial cocentration of A(g) is equal to that B(g) . The equilibrium concentration of A(g) and C(g) are equal. K_(c) for the reaction is