If A, B, C are interior angles of `DeltaABC`, the prove that `cosec((A+B)/2)=sec(C/2)`.

Similar Questions

Explore conceptually related problems

If A,B,C are the interior angles of ABC, then prove that cos((A+B)/2)=sin(C/2) .

If A, B, C are interior angles of triangle ABC, prove that :- cos((B+C)/2)=sin(A/2) .

If A, B, C are the angles of DeltaABC then prove that "cosec"^(2)((B+C)/2)-"tan"^(2)A/2=1

If A, B, C are interior angles of triangle ABC, prove that :- sin((A+C)/2)=cos (B/2) .

If A, B, C are interior angles of triangle ABC, prove that :- 1+cot^2((B+C)/2)=sec^2 "A/2 .

If A, B and C are interior angles of a DeltaABC , then show that cot((B+C)/(2))=tan((A)/(2)) .

If A, B, C are interior angles of triangle ABC, prove that :- cos^2(A/2)+cos^2((B+C)/2)=1 .

If A, B, C are interior angles of triangle ABC, prove that :- tan((A+B)/2)=cot "C/2 .

If A, B, C are interior angles of triangle ABC, prove that :- 1+tan^2((B+C)/2)=cosec^2A/2 .