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A particle of mass 2m is projected at an...

A particle of mass `2m` is projected at an angle of `45^(@)` with the horizontal with a velocity of `20sqrt(2)m//s`.After `1 s` of explosion, the particle breaks into two equal pieces. As a result of this one part comes to rest. The maximum height from the ground attained by the other part is `(g = 10 m//s^(2))`

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A particle of 2m is projected at an angle of 45°with horizontal with a velocity of 20sqrt(2) m/s. After 1 sec. explosion takes place and the particle is broken into two equal pieces. As a result of expansion one point comes to rests. The maximum height from the ground attained by the other part is (g=10m//s^(2))

A particle of mass 2m is projected at an angle of 45^@ with horizontal with a velocity of 20sqrt2m//s . After 1s explosion takes place and the particle is broken into two equal pieces. As a result of explosion one part comes to rest. Find the maximum height attained by the other part. Take g=10m//s^2 .

A particle of mass 2m is projected at an angle of 45^@ with horizontal with a velocity of 20sqrt2m//s . After 1s explosion takes place and the particle is broken into two equal pieces. As a result of explosion one part comes to rest. Find the maximum height attained by the other part. Take g=10m//s^2 .