intercepts cut by line 12x - 9y = 108

Find the intercepts cut off by the line 2x - 3y+18=0 on the coordinate axes

Find the intercepts cut off the line 2x-y+16=0 on the coordintate axes.

Sum of the intercepts cut off by the line 2x + 3y = 6 on the axes is

The length intercepted by the straight line 12 x - 9y = 108 between the corrdinate axes is

The intercept cut off by a line from y-axis is twice that from x-axis and the line passes throught the point (1,2) .The equation of the line is

The intercept cut off by a line from y-axis is twice than that of from x -axis and the line passes through the point (1,2) . The equation of the line is

x-intercept of line 3x – 4y + 12 = 0 is –4.

Find the sum of the intercepts cut by the axes on the lines x+y=a,x+y=ar,x+y=ar^(2) , ……….where a!=0 and r=1/2