A uranium nucleus `._(92)U^(238)` emits and `alpha`-particle and a `beta`-particle in succession. The atomic number and mass number of the final nucleus will be

A uranium nucleus ""_(92)U^(238) emits an alpha particle and a beta - particle in succession. The atomic number and mass number of the final nucleus will be

A nucleus ._Z^AX emits an alpha -particel. The resultant nucleus emits a beta^(+) particle. The respective atomic and mass numbers of the final nucleus will be

A nucleus ._Z^AX emits an alpha -particel. The resultant nucleus emits a beta^(+) particle. The respective atomic and mass numbers of the final nucleus will be

._(92)U^(238) emits 8 alpha- particles and 6 beta- particles. The n//p ratio in the product nucleus is

._(92)U^(238) emits 8 alpha- particles and 6 beta- particles. The n//p ratio in the product nucleus is

A radioactive element ""_(92) X^(238) emits one alpha - particle and one beta ' particle in succession. What is the mass number of new element formed?

A uranium nucleus (atomic number 92 , mass number 231 ) emits an alpha -particle and the resultant nucleus emits a beta -particles. What are the atomic and mass numbers of the final nucleus? .

A uranium nucleus (atomic number 92 , mass number 231 ) emits an alpha -particle and the resultant nucleus emits a beta -particles. What are the atomic and mass numbers of the final nucleus? .