y=e^(x)+1

The solution of (dy)/(dx) -y=e^(x) , y(0) = 1 , is

The solution of (dy)/(dx) -y=e^(x) , y(0) = 1 , is

Solve (dy)/(dx)-y=e^(x) ,y(0)=1

If e^x+e^y=e^(x+y) , show that (dy/dx)=e^(x-y)((e^y-1)/(1-e^x))

The equation of one of the curves whose slope of tangent at any point is equal to y+2x is (A) y=2(e^(x)+x-1) (B) y=2(e^(x)-x-1) (C) y=2(e^(x)-x+1) (D) y=2(e^(x)+x+1)

Differentiate the following : y=e^(3x)/(1+e^(x))

Find the range of y=(e^(x))/([x]+1),x>=0

plot the graph of |y|=|e^(-x)-1|

The solution of the differential equation dy/dx=e^(y-x)+e^(y+x) ; y(0) = 0 is (1) y=e^x(x+1) (2) e^-y=(e^-x-e^x)+1 (3) e^-y =(e^-x-e^x)-1 (4) e^-y =(e^-x+e^x)+1