If a compound on analysis was found to contain `C=18.5%, h=1.55%,Cl=55.04%` and `O=25.81%`, then its empirical formul is

A compound on analysis was found to contain C = 34.6 %, H = 3.85 % and O = 61.55% .Calculate its empirical formula.

A compound on analysis was found to contain C = 34.6 %, H = 3.85 % and O = 61.55% .Calculate its empirical formula.

A compound on analysis was found to contain C=34.6%, H=3.85% and O = 61.55% . Calculate the empirical formula.

An organometallic compound on analysis was found to contain, C = 64.4%, H= 5.5% and Fe = 29.9%. Determine its empricial formula. (At. Mass of Fe = 56 u).

A compound on analysis was found to contain C=34.6%,H=3.85% and O=61.55%.Calculate it empiricl formula

An organic compound is found to contain C = 54.5%, 0=36.4% and H = 9.1% by mass. Its empirical formula is