Benzene and toluene form an ideal solution. The vapor pressures of pure benzene and pure toluene are `75 mmHg` and `25 mmHg` at `20^(@)C`. If the mole fractions of benzene and toluene in vapor phase are `0.63` and `0.37` respectively, then the vapor pressure of the ideal mixture will be

Benzene and toluene form an ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at T(K) are 50mm Hg and 40 mm Hg respectively. What is the mole fraction of toluene in vapour phase when 117 g of benzene is mixed with 46g of toluene? (molar mass of benzene and toluene are 78 and 92 g mol^(-1) respectively).

Benzene (C_(6)H_(6),78g//mol) and toluene (C_(7)H_(8),92g//mol) from an ideal solution. At 60^@C the vapour pressure of pure benzene and pure toluene are 0.575 atm and 0.184 ,respectively . The mole fraction of benzene in solution of these two chemicals that has a vapour pressure of 0.350 atm at 60^@C

The vapour pressure of pure benzene and toluene are 160 and 60 mm Hg respectively. The mole fraction of benzene in vapour phase in contact with equimolar solution of benzene and toluene is :

Benzene and toluene form ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mixed with 100 g of toluene.

The vapour presssures of pure benzene and toluene are 160 and 60 mm Hg respectively. The mole fraction of benzene in vapour phase in contact with equimolar solution of benzene and toluene is