=(1+a^(2)+b^(2))^(3)

Applying vectors , show that (a_(1)b_(1)+a_(2)b_(2)+a_(3)b_(3))^(2)le (a_(1)^(2)+a_(2)^(2)+a_(3)^(2))(b_(1)^(2)+b_(2)^(2)+b_(3)^(2))

Multiply (1)/(2)a^(2)b-(2)/(3)ab^(2)+b by 6abc:

If (3a+1)^(2) +(b-1)^(2) +(2c-3)^(2)=0 , then value of (3a+b+2c) is

If (a^(3//2)-ab^(1//2)+a^(1//2)b-b^(3//2)) is divided by (a^(1//2)-b^(1//2)) , then the quotient is :

If A=[(1,2,3)],B=[(2),(3),(-1)] then (A+B^(T))^(T)=

A = ((1)/(2),(3)/(2)) , B ((3)/(2),(-1)/(2)) then BA = .....

If A = [(1),(2),(3)], B= [2 - 3, 4] , find AB,

If A=[(1,2,3)],B=[(2),(3),(-1)] and (A+B^(T))^(T)=[(a),(b),(c)] then the descending order of a,b,c is

Value of lambda for which (lambda,lambda^2) lies between the lines |x+2y|=3 is (a) ( -1/2,2) (b) (-3/2,2) (c) (-3/2,1) (d) (-1,3/2)