(" ix ")3x+y-11=0" (3"x-y-1=0

8x+5y-11=0; 3x-4y-10=0

Solve for x and y , 8x + 5y - 11 = 0 3x - 4y - 10 = 0

. If 2x^(2)-5xy+2y^(2)=0 represents two sides of triangle whose centroid is (1,1) then the equation of the third side is (A)x+y-3=0 (B) x-y-3=0 (C) x+y+3=0 (D) x-y+3=0

Solve the pair of equations. 7x-5y-11=0, 3x+2y-13=0

For the circle x^(2)+y^(2)-6x-6y+5=0" the lines "3x+y-2=0, x+7y-11=0 are

Draw graphically 3x+2y-11=0,2x-3y+10=0

The normal at the point (1,1) on the curve 2y+x^(2)=3 is (A) x+y=0 (B) x-y+1=0x-y+1=0x-y=0

If the co-ordinates of A and B are (1,1)and (5,7), then the equation of the perpendicular bisector of the line segment AB is............... A) 2x+3y=18 B) 2x-3y+18=0 C) 2x+3y-1=0 D) 3x-2y+1=0