x^(2)-bx-(a+3b)(a+2b)

Solve: (x^2-ax)/b+(x^2-bx)/a+(x^2-3ax-3bx)/(a+b)=0 ]

Let f(x)=3sqrt(a-x^(3)+3bx^(2)-3bx+b^(3)+b) Find b.If f(x) is inverse of itself.

Solve the equations : x^(2)+2bx-b^(2)=a^(2)-b(b-2x)

If (2x-1) is exactly divides 6x^(2)+ax-4 and bx^(2)-11x+3 ,then the value of b^(2)-a^(2)+a-b is

If x = a^(1/3) b^(-1/3) + a^(-1/3) b^(1/3) then prove that a(bx^(3) - 3bx -a) = b^(2)

If x+(a)/(x)=b then the value of (x^(2)+bx+a)/(bx^(2)-x^(3)) is

Factorise : (ii) 3a^(2) x - bx + 3a^(2) - b

If (1)/((a^(2)-bx)(b^(2)-ax))=(A)/(a^(2)-bx)+(B)/(b^(2)-bx) , then the value of A and B respectively would be _________.

A root of the equation (a+b)(ax+b)(a-bx)=(a^(2)x-b^(2))(a+bx) is

Factorize: a^(3)x^(3)-3a^(2)bx^(2)+3ab^(2)x-b^(3)