In the figure below, ABCD is a square , MDC is an equilateral triangle. Find the value of x.

ABCD is a square and DEC is an equilateral triangle. Prove that AE = BE.

ABCD is a square and DEC is an equilateral triangle. Prove that AE = BE.

In the given figure, ABCD is a square and DeltaBCT is an equilateral triangle. Find /_BTD .

ABCD is a square and ABE is an equilateral triangle outside the square then

In the adjoining figure, ABCD is a square and PAB is an equilateral triangle. Find : (i) angleAPD (ii) anglePDC (iii) angleDPC (iv) Prove that DP = CP

In the adjoining figure, ABCD is a square and PAB is an equilateral triangle. Find : (i) angleAPD (ii) anglePDC (iii) angleDPC (iv) Prove that DP = CP

In the given figure, ABCD is a square of side 6 cm and CDE is an equilateral triangle. Find the perimeter of the figure.