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सरल रेखा (x+6)/(1)=(y-2)/(2)=(z+1)/(4) ...

सरल रेखा `(x+6)/(1)=(y-2)/(2)=(z+1)/(4)` पर बिंदु (-6, 2, -1) से 3 दूरी पर एक बिंदु के नियामक हैं

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Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .