Property 10 For any natural number m greater than `1 (2m, m^2 - 1, m^2 + 1)` is a pythagorean triplet .

Property 10 For any natural number m greater than 1(2mm^(2)-1m^(2)+1) is a pythagorean triplet if m^(2)+n^(2)=p^(2)

For every natural number m, (2m -1, 2m^2-2m, 2m^2–2m + 1) is a pythagorean triplet. True or false

For natural number m gt 1, 2m, (m^(2)-1), (m^(2)+1) are ________.

Solve the any one of following sub questions: If m and n are two distinct numbers then prove that m^(2) - n^(2), 2mn and m^(2) + n^(2) is a pythagorean triplet.

If a and b are natural numbers and a > b, then show that (a^(2) + b^(2)), (a^(2) - b^(2)),(2ab) is a pythagorean triplet. Find two Pythagorean triplets using any convenient values of a and b.

If a and b are natural numbers and a gt b, then show that (a^(2) + b^(2)), (a^(2) - b^(2)),(2ab) is a pythagorean triplet. Find two Pythagorean triplets using any convenient values of a and b.

Can you find more triplets. For any natural number m gt 1 . We have (2m)^(2) + (m^(2) -1)^(2) = (m^(2) + 1)^(2) So, 2m, (m^(2) -1), (m^(2) + 1) form a pythagorean triplet Try to find some more Pythagoren triplets using this form.

If m and n are two distinct numbers such that m >n, then prove that m^2-n^2 ,2mn and m^2+n^2 is a Pythagorean triplet.

M.A. is always greater than 1 in

If a and b are natural numbers and a gt b, then show that (a^(2)+b^(2)),(a^(2)-b^(2))_,(2ab) is a Pythagorean triplet. Find two Pythagorean triplets using any convenient values of a and b.