Calculate `pH` of the half cell `:`
`Pt,H_(2)(1 atm)|H_(2)SO_(4)" "E^(c-)=-0.3V`

Calculate EMF of the following half cells : a. Pt, H_(2)(2 atm)|HCl(0.02M)" "E^(c-)=0V b. Pt , Cl_(2)(10 atm)|HCl(0.1 M)" "E^(-c)=1.36V

Calculate EMF of the following half cells : a. Pt, H_(2)(2 atm)|HCl(0.02M)" "E^(c-)=0V b. Pt , Cl_(2)(10 atm)|HCl(0.1 M)" "E^(-c)=1.36V

Calculate EMF of the following half cells : a. Pt, H_(2)(2 atm)|HCl(0.02M)" "E^(c-)=0V b. Pt , Cl_(2)(10 atm)|HCl(0.1 M)" "E^(-c)=1.36V

Calculate the pH of the following half-cells solutions : (a) PtH_(2) ("1 atm")|H^(+) (HCl), " "E=0.25" volt" (b) PtH_(2) ("1 atm")|H^(+) (H_(2)SO_(4))," "E=0.3" volt"

Calculate e.m.f. of half cells given below : (a) {:(Pt_(2)),(4atm):}|{:(H_(2)SO_(4)),(0.02 M):} E_(OP)^(@) = 0 V (b) {:Fe:}|{:(FeSO_(4)),(0.2 M):} E_(OP)^(@) = 0.44 V (c) {:(Pt_(Cl_(2))),(10atm):}|{:(HCl),(0.02 M):} E_(OP)^(@) = -1.36 V

Consider the half - cell : Pt|H_(2)"(1 atm)"|H_(2)SO_(4) . If the reduction potential of the half - cell at 25^(@)C be 0.3 V, then determine the pH of H_(2)SO_(4) solution in the half - cell.

Calculate the reduction potential of the following electrodes : a. Pt,H_(2)(4 atm)|H_(2)SO_(4)(0.01M) b. Pt,H_(2)(1 atm)| HCl (0.2 M) c. Calculate the potential of hydrogen electrode in contact with a solution whose i pH=5" "ii. pOH=4

Calculate the reduction potential of the following electrodes : a. Pt,H_(2)(4 atm)|H_(2)SO_(4)(0.01M) b. Pt,H_(2)(1 atm)| HCl (0.2 M) c. Calculate the potential of hydrogen electrode in contact with a solution whose i pH=5" "ii. pOH=4

Calculate the reduction potential of the following electrodes : a. Pt,H_(2)(4 atm)|H_(2)SO_(4)(0.01M) b. Pt,H_(2)(1 atm)| HCl (0.2 M) c. Calculate the potential of hydrogen electrode in contact with a solution whose i pH=5" "ii. pOH=4

Calculate the pH of the following half cells solutions and also the molarity of acids: {: (Pt_(H_(2))),(atm):}|{:H_(2)SO_(4):} " " E = 0.05 (b) {: (Pt_(H_(2))),(atm):}|{:HCl:} " " E = 0.1 V