1+sin2 theta=(sin theta+cos theta)^(2)

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

(xv) (cos^2 theta) / (1- tan theta) +( sin^3 theta)/ (sin theta - cos theta) = 1 + sin theta cos theta

Prove that, (1 + sin 2 theta - cos 2 theta)/(sin theta + cos theta)= 2 sin theta

(sin theta-cos theta)/(sin theta+cos theta)+(sin theta+cos theta)/(sin theta-cos theta)=(2)/((2sin^(2)theta-1))

Prove: (cos^2theta)/(1-tan theta) + (sin^3 theta)/(sin theta - cos theta ) = 1 + sin theta cos theta

The maximum value of the expression (1)/(sin^(2)theta+3sin theta cos theta+5cos^(2)theta)

The maximum vale of the expression (1)/(sin^(2)theta+3sin theta cos theta+5cos^(2)theta) is

The maximum value of the expression (1)/( sin^(2) theta + 3 sin theta cos theta + 5cos^(2) theta) is