Find the velocity of escape at the moon. Given that its radius is `1.7xx10^(6)` m and the value of 'g' is `1.63 ms^(-2)`.

Find the velocity of escape at the earth given that its radius is 6.4xx^(6) m and the value of g at its surface is 9.8ms^(-2)

Find the velocity of escape from the sun, if its mass is 1.89xx10^(30) kg and its distance from the earth is 1.59xx10^(8) km. Take G =6.67xx10^(-11) Nm^(2) kg^(-2)

Determine the escape speed of Moon. Given, the radius of Moon is 1.74 xx 10^(6) m , its mass is 7.36 xx 10^(22) kg . Does your answer throw light on why the moon has no atmosphere? G = 6.67 xx 10^(-11) n m^(2) kg^(-2) .

Determine the escape velocity of a body from the moon. Take the moon to be a uniform sphere of radius 1.74 xx 10^(6) m , and the mass 7.36 xx 10^(22) kg ? ( G = 6.67 xx 10^(-11) Nm^(2) kg^(-2))

Determine the value of the escape velocity from the surface of the moon. The radius of the moon= 1.7xx10^6m and its mass = 7.35xx10^(22)kg. (G=6.67xx10^(-11)N*m^2*kg^(-2))

Determine the escape velocity of a body from the moon. Take the moon to be a uniform sphere of radius 1.76 xx 10^(6) m , and mass 7.36 xx 10^(22) kg . Given G=6.67 xx 10^(-11) Nm^(2) kg^(-2)

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .

The mass of the moon is 7.34xx10^(22) kg and the radius is 1.74xx10^(6) m . The value of gravitation force will be

Weight of 1 kg becomes 1//6 on moon. If radius of moon is 1.768xx10^(6) m , then the mass of moon will be

Calculate the value of g on the Moon, it its mass is 7.4xx10^(22) kg and radius is 1740 km.