[" 4.If the pressure of "H_(2)" gas is increased from "1" atm to "100" atm.Keeping "H^(+)" concentration constant at "],[1M" ,the voltage of Hydrogen half cell at "25^(@)C" will be "],[0]

If the pressure of H_2 gas is increase from (1) atm to 100 atm. Keeping H^+ concentration constatn at 1 M, the veltage of hydrogen half cell at 25^@ C will be .

If the pressure of hydrogen gas is increased from 1 atm. To 100 atm, keeping the hydrogen ion concentration constant at 1 M, the reduction potential of the hydrogen half cell is at 25^(@)C will be

If the pressure of a gas at constant volume changes from 2 atm to 1 atm. The temperature changes from 0^@C

At constant temperature, the pressure of V mL of a dry gas was increased from 1 atm to 2 atm. The new volume will be :

At constant temperature, the pressure of V mL of a dry gas was increased from 1 atm to 3 atm. The new volume will be :

At constant temperature, the pressure of VmL of a dry gas was increased from 1 atm to '2 ~atm .' The new volume will be

At 27^(@)C it was observed in the hydrogenation of a reaction, the pressure of H_(2)(g) decreases form 10 atm to 2 atm in 10 min . Calculate the rate of reaction in M min^(-1) (Given R = 0.08 L atm K^(-1) mol^(-1) )