[9" balls are to be placed in "9" boxes,and "5" of "b],[" balls can not fit into "3" small boxes.The nut "],[" ber of ways of arranging one ball in each "],[" the boxes is "]

9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes.the number of ways of arranging one ball in each of the boxes is

9 balls are to placed in 9 boxes : and 5 of the balls cannot fit into 3 small boxes the number of ways of arranging one ball in each of the boxes is

7balls (distinct) are to be placed in 7 boxes (distinct) and 4 of the balls can not fit into 2 small boxes.The number of ways of arranging one ball in each of the boxes is X .Let P be the probability of selected divisor in the list of divisors of X is in the Form of 4n+1 ,then find 6P (where n in N)

5 balls are to be placed into 3 boxes such that no box remains empty The number of ways in which this can be done.

Five balls are to be placed in three boxes in how many diff. ways can be placed the balls so that no box remain empty if .