(sin x+cos x)/(sqrt(sin2x))

int_(pi/6)^(pi/3) (sin x+ cos x)/(sqrt(sin 2x))dx

int_(pi/6)^(pi/3) (sin x+ cos x)/(sqrt(sin 2x))dx

" Q."3 (d)/(dx){(sin x+cos x)/(sqrt(1+sin2x))} =

int(sin x+cos x)/(sqrt(1+sin2x))dx

Write a value of int(sin x+cos x)/(sqrt(1+sin2x))dx

The value of int(sin x+cos x)/(sqrt(1-sin2x))dx is equal to sqrt(sin2x)+C(b)sqrt(cos2x)+C(c)+-sin x-cos x)+C(d)+-log(sin x-cos x)+C

int(sin x-cos x)/(sqrt(1-sin2x))e^(sin x)cos xdx, where [x in((pi)/(4),(3 pi)/(4))]

int (sin x - cos x )/(sqrt(sin 2x)) dx =

int(sin x cos x)/(sqrt(1+sin^(2)x))dx=

Solve the following integration int (sin x+cos x)/(sqrt(1+sin 2x))*dx , here (sin x + cos x) gt 0