Home
Class 12
PHYSICS
[" 13.The distance covered by a particle...

[" 13.The distance covered by a particle moving in a straight "],[" line from a fixed point on the line is "s" .Where "],[s^(2)=at^(2)+2bt+c," then acceleration is proportional'to "],[[" (a) "s^(-2)," (b) "s^(-3)],[" (c) "s^(-1/2)," (d) None of these "]]

Promotional Banner

Similar Questions

Explore conceptually related problems

The distance covered by a particle moving in a straight line from a fixed point on the line is s where s^(2)=at^(2)+2bt+c .Then prove that acceleration is proportional to s^(-3) .

The distance covered by a particle moving in a straight line from a fixed point on the line is s , where s^2=a t^2+2b t+c dot Then prove that acceleration is proportional to s^(-3)dot

The distance covered by a particle moving in a straight line from a fixed point on the line is s , where s^2=a t^2+2b t+c dot Then prove that acceleration is proportional to s^(-3)dot

The distance covered by a particle moving in a straight line from a fixed point on the line is s , where s^2=a t^2+2b t+cdot Then prove that acceleration is proportional to s^(-3)dot

If the velocity v of a particle moving along a straight line and its distance s from a fixed point on the line are related by v^(2)=a^(2)+s^(2) , then its acceleration equals

If the velocity v of a particle moving along a straight line and its distance s from a fixed point on the line are related by v^(2)=a^(2)+s^(2) , then its acceleration equals

If a particle moving in a straight line and its distance x cms from a fixed point O on the line is given by x=sqrt(1+t^(2)) cms, then acceleration of the particle at t sec. is

A particle moves in a straight line so that s=sqrt(t) , then its acceleration is proportional to

A particle moves in a straight line so that s=sqrt(t) , then its acceleration is proportional to

A particle moves in a straight line so that s=sqrt(t) , then its acceleration is proportional to