(ln(sec x+tan x))/(cos x)dx=(ln(sec y+tan y))/(cos y)dy

The solution of cos y log (sec x + tan x)dx = cos x log (sec y + tan y) dy is

The solution of the differential equation cos y log (sec x + tan x)dx=cos x log(sec y + tan y)dy is

The solution of the differential equation cos y log(sec x+tan x)dx=cos x log(sec y+tan y)dy is (a) sec^(2)x+sec^(2)y=c(b)sec x+sec y=c(c)sec x-sec y=c(d)Non of these

int sec x ln(sec x+tan x)dx=

int sec x ln(sec x+tan x)dx=

Evaluate: (i) int(sec x)/(log(sec x+tan x)dx) (ii) int(cos ecx)/((log tan x)/(2))dx

int (sec x dx)/(log (sec x +tan x)) =

If y=(sin x)^(tan x)+(cos x)^(sec x), find (dy)/(dx)

If (cos x)^(y)=(tan y)^(x), prove that (dy)/(dx)=(log tan y+y tan x)/(log cos x-x sec y cos ecy)