" (vi) "(x+1)/(x+2)

If graph of y=(x-1)(x-2) is then draw the graph of the following (i) y=|(x-1)(x-2)| (ii) |y|=(x-1)(x-2) (iii) y=(|x|-1)(|x|-2) (iv) |(|x|-1)(|x|-2)| (v) |y|=|(|x|-1)(|x|-2)|

If (x + (1)/(x)) = 2 , then x^(2) + (1)/(x^(2)) = "_________"

Let x_(1) , x_(2) , x_(3) be the solution of tan^(-1) ((2x + 1)/(x +1 )) + tan ^(-1) ((2x - 1)/( x -1 )) = 2 tan ^(-1) ( x + 1) " where x_1 2x_(1) + x_(2) + x_(3)^(2) is equal to

Solve for x : (x - 1)/(2x + 1) + (2x + 1)/(x -1) = 2 , where x ne - (1)/(2) , 1

If ( x )_1a n d( x )_2 are the means of two distributions such that ( x )_1 ( x )_2 (c) x =(( x )_1+( x )_2)/2 (d) ( x )_1<( x )_<( x )_2