int_(0)^(2)1n^(2)+2x-31dx

Evaluate: int_(0)^(1)|5x-3|dx( ii) int_(0)^( pi)|cos x|dx( iii) int_(-5)^(5)|x-2|dx( iv )int_(-1)^(1)e^(|x|)dx(v)int_(0)^(2)|x^(2)+2x-3|dx(v)int_(1)^(4)(|x-1|+|x-2|+|x-3|)dx( vi) int_(1)^(2)|x^(3)-x|dx

int_(0)^(2)(3x^(2)+2x-1)dx=

int_(0)^(2)|1-x^(2)|dx

int_(0)^(2) [x^(2)-1]dx=

Evaluate int_(0)^(2)(2x^2+x+1)dx

int_(0)^(2)(x^(2)-1)dx=

int_(0)^(2)(x^(2)+1)dx

If int_(0)^(1) x e^(x^(2) ) dx=alpha int_(0)^(1) e^(x^(2)) dx , then

If I_(1)=int_(0)^(1) 2^(x^(2)) dx, I_(2)=int_(0)^(1) 2^(x^(3)) dx, I_(3)=int_(1)^(2) 2^(x^(2))dx and I_(4)=int_(1)^(2) 2^(x^(2))dx then

Show that int_(0)^(2)(2x+1)dx = int_(0)^(5)(2x+1)+int_(5)^(2)(2x+1)