A chess game between two grandmasters X and Y is won by whoever first wins a total of two games. X's chances of winning or loosing any perticular game are a, b and c, respectively. The games are independent and a+b+c=1.
The probability that Y wins the match after the 4th game, is

A chess game between two grandmasters X and Y is won by whoever first wins a total of two games. X's chances of winning or loosing any perticular game are a, b and c, respectively. The games are independent and a+b+c=1. The probability that X wins the match, is

A chess game between two grandmasters X and Y is won by whoever first wins a total of two games. X's chances of winning or loosing any perticular game are a, b and c, respectively. The games are independent and a+b+c=1. The probability that X wins the match, is

A chess game between two grandmasters X and Y is won by whoever first wins a total of two games. X's chances of winning or loosing any perticular game are a, b and c, respectively. The games are independent and a+b+c=1. The probability that X wins the match, is

A chess game between two grandmasters X and Y is won by whoever first wins a total of two games. X's chances of winning or loosing any perticular game are a, b and c, respectively. The games are independent and a+b+c=1. The probability that X wins the match after (n+1)th game (nge1) , is

A chess game between two grandmasters X and Y is won by whoever first wins a total of two games. X's chances of winning or losing or draw any particular game are a, b and c, respectively. The games are independent and a+b+c=1. The probability that X wins the match, is

A chess match between two players A and B is won by whoever first wins a total of two games. Probability of A's winning, drawng and losing any particular game are 1/6, 1/3 and 1/2 respectively. (The game are independent). If the probability that B wins the match in the 4^(th) gams is p , then 6p is equal to

A chess game between Kamsky and Anand is won by whoever first wins a out of 2 games. Kamsky's chance of winnig, drawing or lossing a particular game are 2. The games are independent and p+q +r=1 . Prove that the probability that Kamsky wins the match is (p^2(P+3r))/((p+r)^3) .

A chess game between Kamsky and Anand is won by whoever first wins 2 out of 3 games. Kamsky's chance of winning, drawing or lossing a particular game are p,q,r . The games are independent and p+q +r=1 . Prove that the probability that Kamsky wins the match is (p^2(P+3r))/((p+r)^3) .