`(d)/(dx)[tan^(-1)((ax-b)/(bx+a))]=`

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(d)/(dx) [tan^(-1) ((a-x)/(1+ ax))] is

int_(-1)^(1)(d)/(dx)[tan^(-1)((1)/(x))]dx=

(d)/(dx)[tan^(-1)((6x)/(1+7x^(2)))]+(d)/(dx)[tan^(-1)((5+2x)/(2-5x))]=

(d)/(dx)[tan^(-1)((a-x)/(1+ax))] is equal to

(d)/(dx)[tan^(-1)((sinx)/(1+cosx))]=

(d)/(dx)[sec(tan^(-1)x)]=

(d)/(dx)[tan{tan^(-1)((x)/(a))-tan^(-1)((x-a)/(x+a))}]=

d/(dx)[tan^(-1)((a-x)/(1+ax))] is equal to

d/(dx){tan^(-1)((cosx)/(1+sinx))}=

d/(dx) [tan^(-1)(sqrt(x))] =