The equation of the tangent to the parabola `y^(2)=8x` which is perpendicular to the line `x-3y+8=0`, is

The equation of the tangent to the parabola y^(2)=16x, which is perpendicular to the line y=3x+7 is

Find the equation of the tangent of the parabola y^(2) = 8x which is perpendicular to the line 2x+ y+1 = 0

The equation of the tangent to the parabola y^(2)=8x and which is parallel to the line x-y+3=0 is

The equation of the tangent to the parabola y^(2)=8x and which is parallel to the line x-y+3=0 is

The equation of the tangent to the parabola y^(2)=16x and perpendicular to the line x-4y-7=0 is

The equation of the tangent to the parabola y^(2) = 8x, which is parallel to the line 2x-y+7=0 ,will be

The equation of the tangent to the parabola (y-2)^(2)=8(x+1), which is parallel to the line y=2 x-3 is

Find the equation of the tangent to the parabola y^(2) = 8x which is parallel to the line 2x + 2y + 5 = 0 . Find its point of contact.